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Area of a Triangle (Part 2) | Coordinate Geometry | CBSE | Class 10 | MathEpisode from the podcastArea of a Triangle (Part 2) | Coordinate Geometry | CBSE | Class 10 | Math
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Q4. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that cp=ab

Q4. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that cp=ab

Released Tuesday, 29th September 2020
Good episode? Give it some love!
Q4. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that cp=ab

Q4. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that cp=ab

Q4. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that cp=ab

Q4. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that cp=ab

Tuesday, 29th September 2020
Good episode? Give it some love!
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This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

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