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Area of a Triangle (Part 2) | Coordinate Geometry | CBSE | Class 10 | MathEpisode from the podcastArea of a Triangle (Part 2) | Coordinate Geometry | CBSE | Class 10 | Math
Q5. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that 1/p² = 1/a² + 1/b²

Q5. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that 1/p² = 1/a² + 1/b²

Released Tuesday, 29th September 2020
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Q5. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that 1/p² = 1/a² + 1/b²

Q5. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that 1/p² = 1/a² + 1/b²

Q5. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that 1/p² = 1/a² + 1/b²

Q5. ∆ ABC is a right triangle in which angle C = 90° and CD perpendicular AB. If BC = a, CA = b, AB = c and CD = p then prove that 1/p² = 1/a² + 1/b²

Tuesday, 29th September 2020
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