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Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Released Monday, 28th September 2020
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Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Monday, 28th September 2020
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This podcast is a part of a series for, CBSE Class 10 Maths. We recommend that you take a look at our YouTube channel, to enter this new world of virtual learning at its best. || Youtube: Shiksha Abhiyan || t.ly/dN9j8 ||

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