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Midpoint | Coordinate Geometry | CBSE | Class 10 | MathEpisode from the podcastMidpoint | Coordinate Geometry | CBSE | Class 10 | Math
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Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Released Monday, 28th September 2020
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Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Q2. ∆ ABC is right angled at B and D is the midpoint of BC. Prove that AC² = (4AD² - 3AB²)

Monday, 28th September 2020
Good episode? Give it some love!
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